编写函数，接受一个n，n为正整数，左右两种打印方式。要求数字必须对齐

12 11 10 9 8 7 6 5 4 3 2 1   11 10 9 8 7 6 5 4 3 2 1      10 9 8 7 6 5 4 3 2 1         9 8 7 6 5 4 3 2 1           8 7 6 5 4 3 2 1             7 6 5 4 3 2 1               6 5 4 3 2 1                 5 4 3 2 1                   4 3 2 1                     3 2 1                       2 1                         1                         1                       2 1                     3 2 1                   4 3 2 1                 5 4 3 2 1               6 5 4 3 2 1             7 6 5 4 3 2 1           8 7 6 5 4 3 2 1         9 8 7 6 5 4 3 2 1      10 9 8 7 6 5 4 3 2 1   11 10 9 8 7 6 5 4 3 2 112 11 10 9 8 7 6 5 4 3 2 1 补空格法

def trangle2(n):    nums = [i for i in range(n,0,-1)]    length = len(nums)        for i in range(length):        for j in range(length):            if i<=j:                print('{:>{}}'.format(nums[j],len(str(nums[j]))+1),end='')            else:                print('{}'.format(' '*(len(str(nums[j]))+1)),end='')        print()    for i in range(length):        for j in range(length,0,-1):            if i+1>=j:                print('{:>{}}'.format(nums[-j],len(str(nums[-j]))+1),end='')            else:                print('{}'.format(' '*(len(str(nums[-j]))+1)),end='')        print()

靠右对齐法

def trangle_print(n):    nums = ' '.join(str(i) for i in range(n,0,-1))    width = len(nums)    start = -1    step = 2    points = {10**i for i in range(1,3)}    for i in range(1,n+1):        print('{:>{}}'.format(nums[start:],width))        if i+1 in points:            step += 1        start = start -step

 

字符串切割法

def trangle1(n):    nums = ' '.join([str(i) for i in range(n,0,-1)])    length = len(nums)    print(nums)    for i in range(len(nums)):        if nums[i] ==' ':            print('{}{}'.format(' '*(i+1),nums[(i+1):]))                for j in range(len(nums)-1,0,-1):        if nums[j] == ' ':            print('{}{}'.format(' '*(j),nums[j:]))    print(nums)